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Quiz Chapter 7: Measures of Dispersion for Grouped Data

10 questions · Form 5 Mathematics Bab 7: Measures of Dispersion for Grouped Data

Question 1 of 10Score: 0

For the class interval 20 - 29, what is its lower boundary if the preceding class interval is 10 - 19?

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1. For the class interval 20 - 29, what is its lower boundary if the preceding class interval is 10 - 19?

  1. A. 19.5
  2. B. 20.0
  3. C. 19.0
  4. D. 24.5
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Answer: A

Lower boundary = Upper limit of previous class + Lower limit of current class2 = 19 + 202 = 19.5.

2. For N = 200, the first quartile Q₁ occurs at a cumulative frequency of:

  1. C. 50
  2. A. 25
  3. B. 100
  4. D. 150
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Answer: C

Position of Q₁ = (14) × 200 = 50.

3. The interquartile range of a grouped dataset is defined as:

  1. A. Q₃ - Q₁
  2. B. Q₃ - Q₂
  3. C. Q₂ - Q₁
  4. D. Max value - Min value
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Answer: A

Interquartile range = Third Quartile (Q₃) - First Quartile (Q₁).

4. Given ∑f = 50, ∑fx = 300, and ∑fx² = 2300, calculate the mean x̄.

  1. A. 6
  2. B. 46
  3. C. 60
  4. D. 10
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Answer: A

Mean x̄ = ∑fx / ∑f = 30050 = 6.

5. If total frequency N = 80, at what cumulative frequency do you locate the third quartile (Q₃) on an ogive?

  1. C. 60
  2. A. 20
  3. B. 40
  4. D. 75
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Answer: C

Q₃ corresponds to (34) × N = (34) × 80 = 60.

6. If all frequencies in a grouped dataset are multiplied by a constant factor of 2, what happens to the mean x̄?

  1. A. The mean remains unchanged
  2. B. The mean is multiplied by 2
  3. C. The mean is multiplied by 4
  4. D. The mean is halved
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Answer: A

Multiplying frequencies uniformly scales total frequency ∑f and ∑fx by 2, leaving mean x̄ = 2∑fx2∑f unchanged.

7. Calculate the class size for the class interval 15 - 19.

  1. A. 5
  2. B. 4
  3. C. 4.5
  4. D. 17
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Answer: A

Lower boundary = 14.5, Upper boundary = 19.5. Class size = 19.5 - 14.5 = 5.

8. What is the standard deviation σ for a dataset with a variance of 16?

  1. A. 4
  2. B. 256
  3. C. 8
  4. D. 2
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Answer: A

Standard deviation σ = √(Variance) = √16 = 4.

9. Using ∑f = 50, ∑fx = 300, and ∑fx² = 2300, find the variance σ².

  1. A. 10
  2. B. 46
  3. C. 36
  4. D. 100
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Answer: A

Variance σ² = (∑fx² / ∑f) - (x̄)² = (230050) - 6² = 46 - 36 = 10.

10. For a cumulative frequency distribution of N = 120, what cumulative frequency corresponds to the 60th percentile (P₆₀)?

  1. A. 72
  2. B. 60
  3. C. 80
  4. D. 90
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Answer: A

Position of P₆₀ = (60100) × 120 = 72.

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